00:01
Hello students in this question, brad's experiment using copper is been done and we need to find out the coefficient of linear expansion of copper which is taken as alpha.
00:11
Now in this question it is given that at temperature t1 to be equal to 300 kelvin a peak is been obtained at a particular angle of theta 1 which is equal to 25 .23 degree.
00:25
Similarly, at temperature t2 to be equal to 500 kelvin, the same peak is been obtained for a different angle theta 2 to be equal to 25 .14 degree.
00:38
And here, the temperature difference can be taken as delta t which is equal to t2 minus t1.
00:45
The above substitute in the value of t2 and t1 in this equation and under gue simplification, we get the value of change in temperature delta t2 to be equal to 200.
00:55
Kelvin.
00:56
Now in this question it is said that for a temperature t1, the lattice distance is taken as modetta d.
01:02
On the hand, for the temperature t2, the lattice distance is taken as d -d -d -which will be equal to d plus alpha -d into delta -t.
01:13
Now according to the brax equation, we know that n -lamda will be equal to d into sine theta...