A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=1086 and x=526 who said "yes." Use a 90% confidence level. a) Find the best point estimate of the population proportion p. p= 0.484 (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E=
Added by Jennifer W.
Step 1
Given that p = 0.484 and n = 1086, we have: SE = sqrt(0.484 * (1 - 0.484) / 1086) SE = sqrt(0.484 * 0.516 / 1086) SE = sqrt(0.249744 / 1086) SE = sqrt(0.0002299) SE ≈ 0.01516 Show more…
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