00:01
Hello everyone we are going to solve this question in this question the first part for first part we are given that x bar that is mean is equals to 26 .3 standard deviation s is equals to 9 .4 and here we are given n is equals to 10 so from here we can find the degree of freedom which is d f is equals to n minus 1 which is equal to 10 minus when that is 9 so in this question we can find the degree of freedom which is d f is equal to n minus 1 which is 9.
00:29
We have to find 99 % confidence interval, confidence interval.
00:41
And also we have to find the error term.
00:44
So these two things we have to find in this question.
00:48
Now let's start with the solution of this question.
00:51
For 99 % confidence level, we have alpha is equals to 1 minus 0 .99.
00:58
So alpha is equal to 0 .01.
01:01
So alpha divided by 2 is equal to 0 .01 divided by 2 which is 0 .005.
01:09
Now so the value of t alpha divided by 2 comma d f is equal to t 0 .005 .9.
01:18
From the table we have this is equal to 3 .250.
01:23
This is our t value.
01:24
Now firstly we find the margin of error.
01:27
So, margin of error is equals to margin of error that is e is equals to t alpha divided by 2df multiplied with s divided by under root 10.
01:42
So by putting the values here we have this is equals to 3 .250 multiplied with 9 .4 which is divided by under root 10...