A researcher is interested in testing whether a new sedative...

A researcher is interested in testing whether a new sedative-hypnotic drug called Zolexify reduces the degree of motor impairment experienced by patients. The researcher knows that the current leading competitor in the marketplace is lorazepam, and she decides to recruit participants from the local area in order to compare the associated drug effects. She has recruited groups of participants and has assigned them to low, medium, or high dose conditions so that reaction time effects can be observed over a 24-hour period. The data that she acquired is below: Zolexify Group Reaction Times: Low dose: 732, 748, 812 Medium dose: 709, 713, 755 High dose: 685, 682, 833 Lorazepam Group Reaction Times: Low dose: 750, 782, 810 Medium dose: 755, 724, 820 High dose: 694, 645, 870

Transcript

00:01 Hello everyone here in this question they said that we have the information of we have the information of grand sum of sigma x is equals to 10 ,883 and the grand sum of grand sum of x is equals to 10 ,883 square is at 79 ,369 .29.

01:00 And we got the n value as, n1 value as 5, n2 value as 5 and also n3 as 5.

01:10 So the total number of, sorry, so the n value will be total n value will be total n value be 5 plus 5 plus 5 which is equal to 50 so the correction of c will be so the coeration of co -reaction of c will be equal to sigma x four square divided by n so here sigma x four square is 10 ,883 fold square divided by n is 50 which will come as 7 ,8, sorry, 7 ,89 ,078, 95, 9709779 .279 .27, as the answer for the c.

02:19 So s t will be equals to sigma x square plus, sigma 1 x squared plus sigma x squared plus sigma x 2 square plus sigma x3 square minus c so by inserting the values into the formula we will get the sht as 24 lakhs 339 ,563 plus 25 lakhs 25 ,698 plus 25 ,698 plus 29608 plus 29 369 sorry 7 895 97 9 .27 so by simplifying this we will get the ssg as 33 ,389 .73 then the ssb will be equals to sigma x square sorry sigma x 4 square divided by n1 plus sigma x square x2 whole square divided by n2 plus sigma x3 whole square divided by n3 minus c so by inserting the values here we will get the equation as 3491 whole square divided by 5 plus 3 ,552 whole square divided by 5 plus 3 ,840 2 ,840 ,000, divided by 5 minus 78 ,000, 9709 .27.

04:23 So by simplifying this, we will get the equation as 3 lakhs, sorry, 3 pro 95 lakhs, 49 ,385 divided by 5 so this will become as so here it is minus 7708 lach 597 7 lakhs 85 ,979 .27 which will be 1 .38 ,097 .73 so 13 ,8997 .73 so s w will be sw ssw will be equals to sst minus ssb so by inserting the values into the formula we will get the equation as 33 ,389 .73 minus 13 ,897 .73.

05:45 So by simplifying this we will get the ssw value as 10097...

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