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Dear students, question is a researcher prepared a 2 .06 molar aqueous solution of calcium per chloride.
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Calculate the boiling point of this solution in degree celsius.
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Kf and kb values for water are given.
00:16
That is molar depression constant and molar elevation constant for water is given.
00:23
Now here let us first we will calculate the molality because for this calculation we need molality but molarity is given.
00:30
So let us calculate molarity.
00:33
For calculating molarity of solution here molality for the solution of the solution molarity is given.
00:41
So let us assume volume of solution equal to 1 liter.
00:51
Now we have volume 1 liter and molarity.
00:53
Therefore moles of solute we can find out.
00:57
Moles of solute equal to volume multiplied by molarity.
01:10
So 1 multiplied by 2 .06 that is 2 .06 moles of solute equal to 2 .06.
01:18
Now here volume of solution is 1 liter...