A resistance divider of 1400 kV (impulse) has a high voltage arm of R1 = 16 k?. The low voltage arm resistor R2 consists of 16 resistors (250 ? each) connected in parallel. The divider is connected to a CRO through a coaxial cable of surge impedance Zk = 75 ? and terminated at the other end through a resistor of R = 75 ?, as shown in the diagram. Calculate the divider ratio V1/V2.
Added by Richard C.
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First, we need to find the equivalent resistance of the low voltage arm (R2). Since there are 16 resistors of 250 ohms each connected in parallel, we can use the formula for parallel resistors: 1/R2 = 1/R3 + 1/R4 + ... + 1/R18 1/R2 = 16 * (1/250) R2 = 250/16 = Show more…
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