00:01
Hi, in this question, we have a resistor and capacitor.
00:04
And they're connected in series across an ac generator.
00:08
So the voltage is given by vt equals to v0 cos of omega t.
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Then we have v0, which is 120 volt.
00:19
Omega is given as 120 pi radian per second.
00:24
Resistance r is 300 ohm, and capacitance is 4 .5 microfarad.
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So in part a, we have to calculate the magnitude of impedance.
00:35
So impedance z is calculated as under root r squared plus 1 upon omega c whole squared, which gets the value of z as equals to under root 300 squared plus 1 upon 120 pi into 4 .5 into 10 raised to power minus 6 whole squared.
00:58
So on solving this, we get the value of z as 661 .409 ohms.
01:05
Now moving on to the b part, in which we have to write the amplitude of current through the resistor...