A resistor R2=2.0 Ω is mounted in parallel with a resistor R3=9.0 Ω, and this combination is connected in series with a resistor R1=8.0 Ω and a 12 Volts battery. What is the power dissipated in the R2 resistor?
Added by Nancy R.
Step 1
Given R2 = 2.0 Ω and R3 = 9.0 Ω. Using the formula for calculating the total resistance of two resistors in parallel: 1/Rt = 1/R2 + 1/R3 1/Rt = 1/2 + 1/9 1/Rt = 9/18 + 2/18 1/Rt = 11/18 Rt = 18/11 Ω Rt ≈ 1.6363 Ω Show more…
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