A resistor with resistance $R$ is connected to a battery that has emf 12.0 V and internal resistance $r =$ 0.40$\Omega$. For what two values of $R$ will the power dissipated in the resistor be 80.0 W?
Added by Kelly B.
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Given that EMF = 12.0 V and \(r = 0.40 \Omega\), we have: \[I = \frac{12.0}{R + 0.40}\] Show more…
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A resistor with resistance $R$ is connected to a battery that has emf 12.0 $\mathrm{V}$ and internal resistance $r=0.40 \Omega .$ For what two values of $R$ will the power dissipated in the resistor be 80.0 $\mathrm{W} ?$
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