00:01
For member ac that is p is equal to 720 kn after that a is equal to 2200 mm square after that e is equal to 76 gpa after that α is equal to 23 multiplied by 10 to the power of 6 per degree celsius.
00:38
Now for member bd, this a is equal to again 830 mm square after that e is equal to 160 gpa after that α is equal to 17 .3 multiplied by 10 to the power of 6 per degree celsius and at final t1 is equal to 20 degree celsius temperature is given.
01:18
Now in this gap between the beam, we have the diagram, so gap between beam that is also 1 .2 mm.
01:27
Okay, so these are things we have and now we will proceed.
01:32
Okay, so how it is done? so here we have the diagram, let us do a small diagram over here to understand this purpose what it is exactly.
01:41
So this is e to c, okay b and this is d to f, d.
01:49
Okay, this is a diagram we have in the question only.
01:52
So, this is 230 mm and this is 320 mm.
01:59
Now we have to find out the stress acting on section.
02:02
Okay, we have to find out stress acting on section ae and ce...