5 \, m$, the final length as $L = 55 \, cm = 0.55 \, m$, and the tensile load as $F = 5.85 \, N/m^2$. The area is not given directly, but we can assume it's constant throughout the process. The change in length is $\Delta L = L - L_0 = 0.55 \, m - 0.5 \, m = 0.05
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