00:01
For this question, we'll be doing several things with density.
00:06
The density is equal to the mass divided by the volume.
00:11
So if we know the rock has a mass of 15 .25 grams, we simply divide it by the volume of the rock, which will be the change in volume of the water in the graduated cylinder.
00:28
The final volume was 15 .17 milliliters.
00:32
The original volume was 55.
00:35
0 .78 milliliters.
00:38
So if we subtract these two numbers, we're going to get only three significant figures.
00:47
With three significant figures in the denominator and five in the numerator, we're limited to just three significant figures when reporting our density, 6 .37 grams per milliliter.
01:01
Then for the second question, we want to calculate the volume.
01:06
Rearrangement of the density equation tells us volume is equal to mass divided by density.
01:13
The mass was provided at 0 .370 grams and the density of aluminum was provided at 2 .70 grams per centimeter cubed.
01:26
Dividing these two numbers each with three significant figures gives us a volume of 0 .137 centimeters cubed to three significant figures.
01:36
Now that we know the volume of the sample and we know that the volume will be the length times the width times the thickness, then we can calculate the thickness...