00:01
Let's discuss this question.
00:01
So here the rocket of mass 3 .63 multiplied by 10 .000 to 5 kg in flight near the earth surface.
00:08
So we need to find the magnitude in the direction.
00:11
So here we can say mass of rocket, that is, m is given as 3 .63 multiplied by 10 raised to 3 kilograms.
00:25
And here magnitude of crust, that is, t, will be equal to 8 .01 multiplied by 10 .5 to 3 kilograms.
00:37
And here, magnitude of crust, that is, t will be equal to 8 .01, by 10 raised to 6 newton.
00:40
So here we can say direction of thrust above horizontal.
00:55
That is theta is equal to 53 .6 degree.
00:59
So here we can say gravitational force is always downward.
01:16
So w x is equal to 0 and w y is equal to m multiplied by minus g.
01:24
So this will be equal to 3 .63 multiplied by 10.
01:28
10 raised to 5 multiplied by minus 9 .8 and this is equal to minus 35 .58 multiplied by 10 to 5 newton.
01:38
Now further here we can say that t x that is equal to t cos theta so this will be equal to 8 .01 multiplied by 10 to 6 multiplied by plus 53 .6 and this is equal to 4 .75 multiplied by 10 is to 6 newton.
01:57
Now further here we can say, ti is equal to t sine theta.
02:03
So this is equal to 8 .01 multiplied by 10 raised to 6 multiplied by sign, 53 .6 and this is equal to 6 .45 multiplied by 10 raised to 6 newton...