Question

"A rod of length I (laterally thermally insulated) of the uniform cross-sectional area A consists of a material whose thermal conductivity varies with temperature as K=K/a+bT , where Ko, a and b are constants. Tį and T2 (< Tı) are the temperatures of two ends of the rod. Then, the rate of flow of heat across the rod is"

Name: a rod of length i laterally thermally insulated of the uniform cross sectional area a consists of a material whose thermal conductivity varies with temperature as kkabt where ko a and b are constants
Uploaded: 2022-05-01T15:12:25-08:00
Duration: 2 min 57 s
Channel: Jaya M
Description: a rod of length i laterally thermally insulated of the uniform cross sectional area a consists of a material whose thermal conductivity varies with temperature as kkabt where ko a and b are constants

          "A rod of length I (laterally thermally insulated)
of the uniform cross-sectional area A consists
of a material whose thermal conductivity varies
with temperature as K=K/a+bT ,  where Ko,  a and b are constants. Tį and T2 (< Tı) are the
temperatures of two ends of the rod. Then, the
rate of flow of heat across the rod is"

Added by Arun B.

A Complete Resource Book in Physics for JEE Main

Sanjeev Kumar 1st Edition

Chapter 11

Instant Answer

Solved by Expert Jaya M

05/01/2022

Step 1

Step 1: Start with the equation \( \frac{dQ}{dT} = -K \cdot A \frac{dT}{dx} \). Show more…

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"A rod of length I (laterally thermally insulated) of the uniform cross-sectional area A consists of a material whose thermal conductivity varies with temperature as K=K/a+bT , where Ko, a and b are constants. Tį and T2 (< Tı) are the temperatures of two ends of the rod. Then, the rate of flow of heat across the rod is"