That is, for triangle ABC, \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\), where \(a\), \(b\), and \(c\) are the lengths of the sides, and \(A\), \(B\), and \(C\) are the angles opposite those sides, respectively.
Given that the room is 8.0m wide, we
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