Question

A rotating object's angular position is given by O(t) = 1.46t^2 + 7.10t + 2.75 rad, where t is measured in seconds. Find the following: (a) The object's angular speed when t = 3.40 s (rad/s). (b) The magnitude of the angular acceleration when t = 3.40 s (rad/s).

Name: a rotating objects angular position is given by ot 146t2 710t 275 rad where t is measured in seconds find the following the objects angular speed when t 340 s rads b the magnitude of the a 65523
Uploaded: 2022-03-25T11:45:02-08:00
Duration: 2 min 2 s
Channel: Prabhu Ramji
Description: a rotating objects angular position is given by ot 146t2 710t 275 rad where t is measured in seconds find the following the objects angular speed when t 340 s rads b the magnitude of the a 65523

          A rotating object's angular position is given by O(t) = 1.46t^2 + 7.10t + 2.75 rad, where t is measured in seconds. Find the following:
(a) The object's angular speed when t = 3.40 s (rad/s).
(b) The magnitude of the angular acceleration when t = 3.40 s (rad/s).

a rotating objects angular position is given by ot 146t2 710t 275 rad where t is measured in seconds find the following the objects angular speed when t 340 s rads b the magnitude of the a 65523

Added by Michael P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

03/25/2022

Step 1

40 \) s. Given: \( \omega(t) = 2.92t - 7.1 \) rad/s Substitute \( t = 3.40 \) s into the equation: \( \omega(3.40) = 2.92(3.40) - 7.1 \) \( \omega(3.40) = 9.928 - 7.1 \) \( \omega(3.40) = 2.828 \) rad/s Show more…

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A rotating object's angular position is given by O(t) = 1.46t^2 + 7.10t + 2.75 rad, where t is measured in seconds. Find the following: (a) The object's angular speed when t = 3.40 s (rad/s). (b) The magnitude of the angular acceleration when t = 3.40 s (rad/s).