00:01
A rubber ball was dropped at the top of a hole.
00:06
For exactly two seconds later, the sound of the rubber ball hitting the bottom was heard.
00:12
The question is, how deep is the hole? hit, the distance that the ball drop object falls is t in seconds.
00:23
It's represented by the formula s equals t6t to the second power.
00:32
The speed of the sounds is 1100 feet per second.
00:37
Approximately how deep is this hole.
00:40
So let t1 represents the traveling time for the ball of seconds to reach the bottom of the hole, and t2, the time the sound reached the top.
00:52
According to the question, the total time is two seconds.
00:55
So we can set that up as t1 plus t2 is equal to 2.
01:01
Thus, to find t2, you need to do 2 minus 2...