A salesman has 8 presentations scheduled for the coming month. Historically, 30% of her presentations have resulted in sales. It is reasonable to assume that her chance of making a sale in any given presentation is not affected by what happens in any other presentation. Find the following probabilities: Answer the following questions based on the scenario: 4.1 What is the probability that he makes 1 sale during the coming month? (5) 4.2 What is the probability that he makes 2 sales during the coming month? (5) 4.3 What is the probability that he makes 3 sales during the coming month? (5) 4.4 What is the probability that he makes no sale during the coming month? (5)
Added by Angela C.
Close
Step 1
3. Show more…
Show all steps
Your feedback will help us improve your experience
Supreeta N and 76 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Binomial Probability Binomial Probability A saleswoman has 6 presentations scheduled for the coming month. Historically, 20% of her presentations have resulted in sales. It is reasonable to assume that her chance of making a sale in any given presentation is not affected by what happens in any other presentation. Find the following probabilities: Answer the following questions based on the scenario: 2.1 What is the probability that she makes 1 sale during the coming month? (5) 2.2 What is the probability that she makes no sale during the coming month? (5)
Supreeta N.
A salesman normally makes a sale (closes) on 60% of his presentations. Assuming the presentations are independent, find the probability of the following. a) He fails to close for the first time on his fifth attempt. b) He closes his first presentation on his fourth attempt. c) The first presentation he closes will be on his second attempt. d) The first presentation he closes will be on one of his first three attempts. a) P(X = 5) = (Round to four decimal places as needed.) b) P(X = 4) = (Round to four decimal places as needed.) c) P(X = 2) = (Round to four decimal places as needed.) d) The probability the first presentation he closes will be on one of his first three attempts is (Round to four decimal places as needed.)
Pratyush R.
A salesman normally makes a sale (closes) on 60% of his presentations. Assuming the presentations are independent, find the probability of the following. a) He fails to close for the first time on his sixth attempt. b) He closes his first presentation on his fifth attempt. c) The first presentation he closes will be on his second attempt. d) The first presentation he closes will be on one of his first three attempts. a) P(X = 6) = (Round to four decimal places as needed.) b) P(X = 5) = (Round to four decimal places as needed.) c) P(X = 2) = (Round to four decimal places as needed.) d) The probability the first presentation he closes will be on one of his first three attempts is (Round to four decimal places as needed.)
Adi S.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD