00:01
Hello students, here in this question we have to find out the final volume or the temperature and work done in a reversible adiabatic expansion process.
00:11
So first of all we have to know that for an adiabatic process pressure into volume raised to gamma will be a constant.
00:31
So here we can also write that this gamma will be equal to cp divided by cv with the cp minus cv is equal to r.
00:39
So from this whole equation we can write that gamma can be written in terms of cp can be written as cv plus r divided by cv where the cv value is given in the question as 20 .8 joule per kelvin plus r is universal gas constant value 8 .314 value divided by 20 .8 and here we will get our constant value gamma as 1 .399.
01:12
So here next we can find out its final volume where from the above adiabatic equation pv gamma equal to constant we can write that p1 p2 will be equal to v2 by v1 raised to gamma where the final and the initial pressures are given.
01:30
Initial pressure is 3 .25 and the final pressure is 2 .50 atm that will be equal to v2 divided by v1 raised to the gamma constant we found out as 3 .1 .399.
01:43
So from this we can find that the v2 by v1 will be equal to 3 by 2 5 divided by 2 .50 raised to inverse of 1 .399 and we will get v2 by v1 as 1 .218.
01:58
This is the ratio value okay.
02:00
So from this we can find out final volume by using the idle gas equation nrt divided by p with the number of moles can be taken as 1 and the universal gas constant is 8 .134 and the final temperature is 310 kelvin and the pressure we are taking as 3 .25 into 10 raised to minus 5 and here we will get our final volume value will be equal to 0 .070792 m cube...