00:02
If we assume that x is equal to the mass h2o and y is equal to the mass ethanol, then we know that x plus y gives us the total mass of 49 .6 grams.
00:25
If we assume that there's no volume change when we add them together, then v total should be equal to v.
00:35
Ethanol plus vh2o.
00:43
Well, v total is provided at 54 .2 centimeters cubed.
00:53
The volume of ethanol would be the mass of ethanol divided by its density.
01:05
The density is provided at 0 .789 grams per centimeter cubed.
01:15
The volume of water would be the mass of water divided by its density of 0 .998.
01:25
Now we have two equations and two unknowns.
01:29
If we rearrange this equation, y is equal to 49 .6 minus x, which we can plug in here and then we'll have one equation and one unknown, 54 .2 equals 49 .6 minus x over 0 .789 plus x over 0 .99 .98.
02:01
So dividing each of these into the numerator, we get 54 .2 equals...