A sample of helium gas occupies a volume of 8.69 L at 62°C and 380 torr. If the volume of the gas sample is increased to 10.5 L, while its temperature is increased to 123°C, the resulting gas pressure will be torr.
Added by Jose Antonio C.
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The combined gas law is given by the equation: \(P_1V_1/T_1 = P_2V_2/T_2\) Where: \(P_1\) = initial pressure \(V_1\) = initial volume \(T_1\) = initial temperature \(P_2\) = final pressure \(V_2\) = final volume \(T_2\) = final temperature Show more…
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Adi S.
$64^{\circ} \mathrm{C}$ and 361 torr. If the volume of the gas sample is increased to $8.99 \mathrm{L}$ while its temperature is increased to $114^{\circ} \mathrm{C},$ what will be the resulting gas pressure (in torr)?
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