00:01
Hello students, in this video we are going to solve this question.
00:02
For that let's assume we have 100 grams of sample.
00:05
So 40 grams becomes carbon, 6 .7 grams becomes hydrogen and 53 .29 grams of oxygen.
00:11
So for moles of carbon we have, moles of carbon we have nothing but 40 gram, this divided by 12 .01 gram per mole and that gives us nothing but 3 .33 mole.
00:31
And now for the moles of hydrogen, moles of hydrogen we have 6 .71 gram divided by 1 .01 gram per mole.
00:44
So how much do we get? we get 6 .64 mole.
00:49
And now for we have moles of oxygen.
00:54
And now for moles of oxygen we have 53 .29 gram divided by 16 .00 gram per mole.
01:04
How much do we get? we get 3 .33 mole.
01:08
So this number of moles, let's find the simplest ratio.
01:14
Simplest ratio by common divisor.
01:21
Common divisor.
01:27
So we have divided and found the simplest ratio.
01:30
So the empirical formula is nothing but ch2o.
01:34
This is the empirical formula...