A sample of size n = 44 has sample mean ?x = 55.7 and sample standard deviation s = 9.3. Construct a 98% confidence interval for the population mean ?. Round the answers to one decimal place. A 98% confidence interval for the population mean ? is < ? < .
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Given: Sample mean (x̄) = 55.7 Sample standard deviation (σ) = 9.3 Sample size (n) = 44 Confidence coefficient (t) for 98% confidence level with 43 degrees of freedom = 2.416 Margin of error = t * (σ / √n) Margin of error = 2.416 * (9.3 / √44) Margin of error = Show more…
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