00:01
Hi, in this question for a bomb calorimeter, we need to determine the heat of the reaction.
00:10
For a bomb calorimeter, heat of reaction plus heat of water and heat of bomb will be equal to zero.
00:25
Firstly, we will determine the heat of water which can be determined using formula m -c -d delta -t.
00:35
Here m is mass of water which is given 1 .17 into 10 raised to power 3 grams and comes out 1170 grams.
00:46
Next is delta t that is change in temperature.
00:50
Final minus initial temperature.
00:55
On solving, the value comes out 3 .1 degrees celsius.
01:02
Now on substituting values in the above equation as the specific heat capacity for, for water is 4 .184 jule per gram degree celsius and it comes out 15175 .368 joules.
01:27
Now next we will determine the heat for bomb which is equal to heat capacity multiplied by its change in temperature...