00:01
Hi, so to solve for this, we will use this formula for heat, mass, specific heat, change in temperature.
00:09
Our unknown here is the final temperature, so rearranging this will have change in temperature delta t is equivalent to q, the amount of heat over the mass, and then the specific heat capacity of the substance.
00:21
So the amount of heat is 191 joules, mass of the sample is 13 .4 grams, specific heat capacity of magnesium is 1 .02 joules per gram degree celsius.
00:32
It's not given here, but this could be easily looked up in standard reference materials.
00:37
So we could cancel grams and then we could cancel joules and our remaining unit will be degree celsius.
00:42
So delta t, change in temperature, is equivalent to 13 .97 degree celsius.
00:48
And remember that the change in temperature, this is final minus initial temperature.
00:54
So rearranging this to solve for the initial temperature, plug in the information that we have, change in temperature is 13 .97 degree celsius...