00:01
Of steam and the mass of the steam is 0 .501 grams.
00:11
My initial temperature is given as 100 degrees c.
00:17
It condenses and it has it into a cup, an insulated cup, that has the mass of water of 4 .45 grams and the initial temperature of the water is 4 .0.
00:35
Degrees c.
00:38
Find the final temp.
00:49
Okay, so we know that the heat of vaporization for water is given as 40 .7 kilojoules per mole and my c of water is given as 4 .18 j over g degrees c.
01:16
So we are going to figure out how much energy is going to be required to vaporize the steam or to condense the steam.
01:35
Sorry about that.
01:43
And that'll be, the energy required to do that will be 0 .501 grams divided by 18 .02 grams per mole.
01:55
This will give me my moles of water times 40 .7 kilojoules per mole times 1 ,000 joules per kilojoule.
02:12
And this will give me 0 .501 times 40 .7 times 1 ,000 divided by 18 .02.
02:26
And that will be 1131 .6 joules to condense steam to 100 degrees c.
02:46
So now let's figure out how much that will raise my temperature of water...