00:01
So today, we're told that we have some water that's been cooled down from 45 degrees celsius to 25 degrees celsius.
00:08
And this is because 20 calories of heat were removed.
00:13
And we're asked to find the mass of the water.
00:16
Okay? and so, we can use the formula that i like to call q equals mc delta t.
00:25
All right.
00:26
Q stands for the amount of heat absorbed or released, and this is in joules.
00:30
M is our mass, c is the specific heat, and delta t is the change in temperature.
00:36
Obviously, we're trying to solve for m, the mass.
00:40
Our first step is to convert the 20 calories that we're given into joules.
00:45
And this is pretty simple...