A school administrator claims that 85% of the students at his large school plan to attend college after graduation. The statistics teacher at this school selects a random sample of 50 students from this school and finds that 76% of them plan to attend college after graduation. The administrator would like to know if the data provide convincing evidence that the true proportion of all students from this school who plan to attend college after graduation is less than 85%. What are the values of the test statistic and P-value for this test?
Added by Joan E.
Step 1
76 - 0.85}{\sqrt{\frac{0.85(1-0.85)}{50}}} \] \[ z = \frac{-0.09}{\sqrt{\frac{0.85(0.15)}{50}}} \] \[ z = \frac{-0.09}{\sqrt{\frac{0.1275}{50}}} \] \[ z = \frac{-0.09}{\sqrt{0.00255}} \] \[ z = \frac{-0.09}{0.0505} \] \[ z = -1.7823 \] ** Show more…
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