Question

A school district wants to know how many students in the district have peanut allergies. Use a 90% confidence interval to estimate the minimum number of students that need to be surveyed in order to yield results that are normally distributed with a standard deviation of 9 and a margin of error of ±0.8 students with peanut allergies. (Recall the following z-scores for each level of confidence: 90% = 1.645, 95% = 1.960, and 99% = 2.575.)

Name: a school district wants to know how many students in the district have peanut allergies use a 90 confidence interval to estimate the minimum number of students that need to be surveyed in or 55478
Uploaded: 2023-08-25T23:56:57-08:00
Duration: 57 s
Channel: James Kiss
Description: a school district wants to know how many students in the district have peanut allergies use a 90 confidence interval to estimate the minimum number of students that need to be surveyed in or 55478

          A school district wants to know how many students in the district have peanut allergies. Use a 90% confidence interval to estimate the minimum number of students that need to be surveyed in order to yield results that are normally distributed with a standard deviation of 9 and a margin of error of ±0.8 students with peanut allergies. (Recall the following z-scores for each level of confidence: 90% = 1.645, 95% = 1.960, and 99% = 2.575.)

Added by Adrian L.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert James Kiss

08/25/2023

Step 1

From the given information, we know that the confidence level is 90%, which means the area under the normal distribution curve is 0.9. Using a z-table or calculator, we can find the z-score that corresponds to this area, which is 1.645. Show more…

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A school district wants to know how many students in the district have peanut allergies. Use a 90% confidence interval to estimate the minimum number of students that need to be surveyed in order to yield results that are normally distributed with a standard deviation of 9 and a margin of error of ±0.8 students with peanut allergies. (Recall the following z-scores for each level of confidence: 90% = 1.645, 95% = 1.960, and 99% = 2.575.)