00:02
Hi, this problem can be solved by using a diagram.
00:06
So let's first write our given.
00:11
We have the number of students who do the field events.
00:15
It was given as 33.
00:19
And the students who do track events is 40.
00:25
And for swimming, we have 23.
00:28
Now we also have students who participated in the field and track events.
00:38
So that's ft equal to 14.
00:43
And streaming and track events, there are students who do both sports number is then.
00:51
And there are students who only did the field event.
01:02
Is 15 students.
01:07
Now we are asked to find, i already have written it here, the number of students who only do swimming and that would be our x and the number of students who only did track we denote that as y and the number of students participating in all the three events that is failed track and swimming we call that our z.
01:32
Now how do we solve for this first we need to fill in our diagram let's start with the intersections first so we are given here ft and s t so we can directly fill that in this is our circle for the field events our circle for track events this is our circle for swimming event and then ft this part right here the intersection of f and t this one is 14 so this one i'll label it this one is 14 so i'll write here 14 and s t where is s t this one right this one right here so our s -t is 10, so we can just write it down here.
02:39
10.
02:40
And now for t, we can fill the circle of t.
02:48
So we have 40.
02:51
It covers all the numbers here in his area.
02:56
So we already have written 14 and 10, so we'll just have to subtract it from 40 minus 10.
03:04
Its answer would be 16 now we also have the value for f and it is 33 so we know that the number of students who do field events is 33 and we already have 14 on an f's circle this one is f but we put already here 14 so we will deduct 14 here.
03:45
14.
03:46
And that should give us, oh, it is already given.
03:53
Here we have f only.
03:56
That means the number of students who do field only.
03:58
So that's 15.
04:01
You can just write directly here 15...