A second-order reaction was observed. The reaction rate constant at 25 oC was found to be 0.003 L/mol and at 70 oC it was found to be 0.029 L/mol. Calculate the activation energy of this reaction in kJ/mol.
Added by Randall N.
Step 1
Step 1: Calculate the activation energy using the Arrhenius equation: \[ \ln \left( \frac{k_2}{k_1} \right) = \frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right) \] Show more…
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