00:01
Alright, so here the question is that a secretary makes three errors per page on average.
00:06
So what is the probability that on the next page she makes fewer than two errors, right? so here we have a poisson distribution, but the value of lambda is three.
00:16
Right now, the formula to be used here is e to the power minus e to the power lambda into minus lambda into lambda to the power x upon x factorial, right? now, in the first part of the question, we have been asked to determine the probability of x is less than two.
00:36
So this is equal to probability of x is zero plus probability of x is one.
00:42
So this is e to the power minus three into three to the power zero upon zero factorial plus e to the power minus three into three to the power one to the power one upon one factorial, right? so here, this is computed as 0 .1991.
00:59
Right now, the next is the probability that each of the next five pages contains fewer than two errors.
01:08
So in this case, the probability here is computed as y is equal to five, for p is equal to 0 .1991, as the probability of less than two errors is on each page is 0 .199, right? so here, this is the desired probability will be equal to 0 .1991 to the power five that is equal to 0 .0003...