00:01
Hello students, we are given a separately excited dc motor with the power 1500 kw, voltage 600, speed 600 rotations per minute, rated current is given 2650 ampere, brush voltage drop will be 2 volt, field power input is 50 kw, axillary resistor value 0 .003645 ohm and axillary inductor is 0 .1 milli henry.
00:44
Now frictional coefficient given 15 newton meter per radian per second.
00:54
Here inductor will be shorted as a dc supply, hence the total input will be taken as 600 into 2650 plus field power which is 50 kw.
01:13
From this we get 1640 kw.
01:18
Next, next we need to calculate losses.
01:24
Here first loss is due to resistance that is copper loss is given by axillary current square into axillary resistor.
01:35
Substituting for current and resistor we obtain 25597 watt.
01:45
Next loss is due to frictional loss.
01:48
First we need to calculate torque due to friction which is given by torque coefficient into rated speed.
01:56
From this we get 942 .48 newton meter...