00:01
Hello, in the question it is given, consider one lcr circuit that is one inductor, one capacitor, one resistor, which are connected in series.
00:13
And this is lcr together it called lcr circuit and the value of resistance, that is r is equal to 20 oan, inductance l is equal to 1 .5 henry and capacitancy is equal to 35 micro -farrid, that is nothing but 35 into 10 .10 per minus 6 fared is the capacitance value.
00:40
And these together, that is lc and r, are together connected to a source of variable frequency, 200 volt ac supply.
00:55
So this is not any dc.
00:57
So this is a ac supply variable with variable.
01:03
Frequency and when the frequency of the supply equals to the natural frequency of the circuit that we need to calculate that is the resonance condition of that is the natural frequency when natural frequency is equal to the supply frequency that is applied frequency at this condition we need to find out the total power so when the natural frequency is equal to the applied frequency, then the set value must be equal to the resistance of the resistor.
01:52
So first we need to calculate irms value, that is the rms value of current, that is nothing but vrms divided by z.
02:01
Since z is equal to r, we can write vrms divided by r, that is 200 divided by 20.
02:09
So rms value of current that is equal to 10 ampere...