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Hi there.
00:01
So for this problem, we have a series rlc circuit that has components with the following values.
00:07
So the inductance is 20 mili henries, that is 20 times 10 to the minus 3 henries, as he's shown in here.
00:16
We also are given the capacitance that is 100 nanofarats that we can express as 100 times 10 to the minus 9 ferrets.
00:25
The resistance is given 20 oms.
00:28
The maximum potential difference is, 100 bowls and this can be expressed because the potential difference is changing with time as the maximum potential difference times sine of omega times the time which is omega is the angular frequency so for part a of this problem we are asked about the resonant frequency of the circuit now the resonant circuit and frequency of a circuit of an rlc circuit is 1 divided by 2 times pi times the square root of the product between the inductance and the capacitance.
01:00
So we just need to simply substitute those values.
01:03
So we will have the inductance that is 20 times 10 to the minus 3.
01:07
Henry's this times the capacitance that is 100 times 10 to the minus 9 ferrets.
01:18
And we take the square root of all of this and the inverse of this.
01:24
So using our calculator, we obtain a frequency of.
01:32
3 ,571 hz.
01:35
So that's a solution for par a of this problem...