00:01
To solve this question we can draw the circuit diagram.
00:04
So this is the voltage, a resistor, inductor and a capacitor.
00:13
So this is a r -l -c circuit.
00:18
So the value of the resistor is 30 ohm, the value of the inductor is 20 milli henry and the value of the capacitor is 2 micro faraday.
00:37
The voltage vs is equals to 90 degree angle.
00:46
As we know that for the condition of series reactance, the value for f0 is equals to 1 by 2 pi square root of lc where this f0 is known as resonant frequency.
01:17
Now upon substituting the values we get f0 equals to 1 divided by 2 pi square root of 20 into 10 to the power minus 3 into 2 into 10 to the power minus 6.
01:43
So this is equals to 10 to the power 4 by 2 pi into 2 which is equals to 0 .775 kilo hertz.
01:58
So this is our value for the resonant frequency.
02:04
Now proceeding towards the next step where we have to consider two cases.
02:11
So for the case 1, it behaves as a dc that is a direct current.
02:25
So the inductor that is present in the circuit will be short and the capacitor that is connected will be open in this condition...