00:01
In the question, we have given cell diameter d0 is 2 .5 cm, tube diameter di is 2 .2 cm, fg is 2 .375 x 106 joule per kg.
00:17
Condensing temperature is 326 k, ti is 290 k, tc out is 308 k.
00:30
Mass rate is 0 .7 kg per second and heat transfer coefficient for condensation is 1500 w per m2 k.
00:45
Initial temperature difference is 326 -290 k which is 36 k.
00:54
Later temperature difference is 326 -308 which is 18 k.
01:03
Now, we will also find delta t ln delta ti -delta to divided by ln delta ti by delta to which is 36 -18 divided by ln 36 divided by 18.
01:25
Hence, delta t ln equals to 25 .97 k.
01:32
Heat transfer of cooling water is given as q equals to m cp delta t equals to 0 .7 x 4 .18 x 308 -290 which is 52 .76 w...