A shop manager has determined that the amount of time customers spend in the shop is approximately normally distributed with a mean of 40 minutes and a standard deviation of 5 minutes. Find the probability that a customer spends between 30 and 35 minutes in the shop.
Added by John C.
Step 1
Given: Mean (μ) = 40 minutes Standard Deviation (σ) = 5 minutes For 30 minutes: z = (x - μ) / σ z = (30 - 40) / 5 z = -2 For 35 minutes: z = (x - μ) / σ z = (35 - 40) / 5 z = -1 Show more…
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