A shunt dc motor operates with speed n1000 rpmn 1000rpm...

A shunt DC motor operates with: Speed, n=1000 rpmn = 1000rpm Generated EMF, Ef=500 V Field current, If=1 A If the field current IfI_fIf is increased to 1.5 Awhile Efremains constant, what will be the new speed nnn?

Transcript

00:01 All right, so let it says that, so let me draw the circuit diagram, okay? so let this is the circuit diagram, okay? so let this is the resistor, and here a motor is connected, okay? motor is connected and this is the sharp of that motor, okay? and it can create a torque and the angular velocity and this is eb okay and the number of r pms n is this is 400 r pms okay r p m right now this is the current going through this direction and this is an inductor okay and this is the other terminal which is 500 words okay now i let this is i if okay and this is rf which is 200 oom okay now let me write it here okay so the power input is let the power in is 25 kilowatt which is 25 thousand watts okay v n i n is 25 000 okay so the input current is 25 000 divided by v n v n is 500 so this will be equal to 50 amp okay now the i f is i if is equal to 500 divided by rip so this is 500 divided by rip so this is 500 divided by 200 which is also 25 mpairs now i a is 500 sorry this is i n this is i n minus i if so this is 50 minus 2 .5 which is 47 .5 emperors okay now if we look at here e b okay so eb is v minus i a r a so this is 500 minus 47 point five times point pipe okay so e b is equal to 47 625 watts all right so this is back emip this is back emf right now let me here in the second part let now now power out will be power output is 25 kilowatt okay and the output current will be equal to power out divided by v so this is 25 times 10 to the power 3 divided by 500 which is 50 emperors okay and let here iip is this is equal to 500 divided by 200 so this is 2 .5 impair now now i a is iip plus i out okay so this is 50 plus 2 .5 which is 52 .5 amper's okay now the eamip of the generator is the emip of the generator this is the emip of generator electromotive pores of generator okay this is equal to v plus i a r a which is nothing but pipe plus 52 .5 times 0 .3.

04:13 Okay.

04:14 So this is equal to 526 .25 volts.

04:19 Okay.

04:20 Now we need in two...

Question

A shunt DC motor operates with: Speed, n=1000 rpmn = 1000rpm Generated EMF, Ef=500 V Field current, If=1 A If the field current IfI_fIf is increased to 1.5 Awhile Efremains constant, what will be the new speed nnn?

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