Question

A signal $x_a(t)$ that is bandlimited to 10 kHz is processed by the following system: $x_a(t)$ $C/D$ $f = 20 kHz$ $f = 20 kHz$ $y(n)$ $y_a(t)$ $\uparrow 10$ $H(e^{j\omega})$ $\downarrow 10$ $D/C$ $\begin{cases} e^{-4j\omega} & |\omega| < \frac{\pi}{10} \\ 0 & \text{otherwise} \end{cases}$ express the output $y_a(t)$ in terms of the input $x_a(t)$.

          A signal $x_a(t)$ that is bandlimited to 10 kHz is processed by the following system:
$x_a(t)$ 
$C/D$
$f = 20 kHz$
$f = 20 kHz$
$y(n)$
$y_a(t)$
$\uparrow 10$
$H(e^{j\omega})$
$\downarrow 10$
$D/C$
$\begin{cases} e^{-4j\omega} & |\omega| < \frac{\pi}{10} \\ 0 & \text{otherwise} \end{cases}$
express the output $y_a(t)$ in terms of the input $x_a(t)$.

A signal xa(t) that is bandlimited to 10 kHz is processed by the following system:
xa(t)
C/D
f = 20 kHz
f = 20 kHz
y(n)
ya(t)
↑ 10
H(e^jω)
↓ 10
D/C
e^-4jω |ω| < (π)/(10)
0 otherwise
express the output ya(t) in terms of the input xa(t).

Added by Joseph S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Amit Srivastava

02/27/2022

Step 1

Step 1: The input signal x_(a)(t) is bandlimited to 10 kHz. Show more…

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A signal x_(a)(t) that is bandlimited to 10 kHz is processed by the following system: express the output y_(a)(t) in terms of the input x_(a)(t). A signal x_(a)(t) that is bandlimited to 10 kHz is processed by the following system: =20 kHz =20 kHz x_(a)(t) t10 +10 y(n) y_(a)(t) C/D H(ejw) D/C TT 10 otherwise express the output y_(a)(t) in terms of the input x_(a)(t)