00:01
In this question, this is the diagram of basically the pandolum.
00:05
And the first part, we need to calculate the speed.
00:10
So, as we know, if i draw the free body diagram for this pendulum, this much distance will be equal to l -cos theta, if theta is this angle.
00:25
Right.
00:26
Therefore, i can say that h will be equal to l minus l -l -cos -theta.
00:35
Will be l 1 minus cos of theta and they have given that the value of l is equal to nothing but 2 .76 2 .76 meter in the first part we need to calculate the period so in the first part time period is equal to 2 pi under root of l divided by g that will be equal to 2 multiplied by 3 .14 multiply by under root of l is 2 .76 divided by g that is 9 .8.
01:12
After calculating this, we will get the time period that will be equal to 3 .3 seconds.
01:23
In the second part, we need to calculate the magnitude of the force on the pendulum bulb.
01:30
Pandolum bulb.
01:32
So according to this, f will be equal to m .g...