00:01
Hello student, to solve the given question, let us first write the time period t equals 2 pi l by g under root.
00:09
Also, omega here is equal to g by l under root.
00:14
So we're using these relations for part a, we can find the time period as t equals 2 multiply by 3 .14, l is 2 .77 divided by 9 .8 under root.
00:30
So from here we get the final answer for part a, that is period of oscillation, equals 3 .34 seconds.
00:38
Now for the next part, we need to find the magnitude of force.
00:43
Here the magnitude of force will be equal to mg sine theta.
00:51
So here plug in the values, we get 1 .4 into 9 .8, multiply by sine of 8 .2 degrees.
01:01
After solving this, we get the final answer for part b, magnitude of force equals 1 .95 newtons.
01:08
Now for the next part, let us first calculate the value for omega, that is equal to g by l, so 9 .8 divided by 2 .77 under root will be equal to 1 .88 radiance per second...