00:01
Hello students, let's do this question.
00:02
Here the sample of unequal to 25 observations are taken.
00:05
The value of x -a equal to 26 .5 standard deviation sigma equal to 4 .4 is given.
00:12
Now we have to find out the conference interval, conference interval for population mean mu.
00:17
So the formula becomes conference interval c i equal to x plus minus z by 2 into sigma power square root of n, where the value of z as 90 % equal to 1 .645.
00:31
Now put the values, then again, conference intervals nigh, equal to x -par, that is 26 .5 plus minus 1 .645 into 4 .4 divided by square root of 25 equal to, equal to 26 .5, 26 .5 plus minus 1 .447 .6 equal to 25 .0524 to 27 .76.
00:58
Now the value of chart at 95 % equal to 1 .96 of the compressantable becomes ci equal to 26 .5 plus minus 1 .96 into 4 .4 divided by square root of 25 equal to 26 .5 plus minus 1 .7248 equal to 24 .772 to 28 .28...