Question

A simply-supported rectangular plate (at all edges) is considered under uniformly distributed load P, as shown in figure below. Z p p Z ILX -Ly- y For the following data: P = 10 kPa, E = 200 GPa, \nu = 0.3, L_x = 1.5 m, L_y = 2.5 m, and thickness t = 3 mm. (a) Determine the maximum displacement ($w_{max}$) in the plate, (b) Obtain the maximum stress ($\sigma_{max}$) inside the plate. (Consider only 2 terms in x and y directions in your $\sum$ calculations.)

          A simply-supported rectangular plate (at all edges) is considered under uniformly distributed
load P, as shown in figure below.
Z
p
p
Z
ILX
-Ly-
y
For the following data: P = 10 kPa, E = 200 GPa, \nu = 0.3, L_x = 1.5 m, L_y = 2.5 m,
and thickness t = 3 mm.
(a) Determine the maximum displacement ($w_{max}$) in the plate,
(b) Obtain the maximum stress ($\sigma_{max}$) inside the plate.
(Consider only 2 terms in x and y directions in your $\sum$ calculations.)

A simply-supported rectangular plate (at all edges) is considered under uniformly distributed
load P, as shown in figure below.
Z
p
p
Z
ILX
-Ly-
y
For the following data: P = 10 kPa, E = 200 GPa, ν= 0.3, Lx = 1.5 m, Ly = 2.5 m,
and thickness t = 3 mm.
(a) Determine the maximum displacement (wmax) in the plate,
(b) Obtain the maximum stress (σmax) inside the plate.
(Consider only 2 terms in x and y directions in your ∑ calculations.)

Added by Stephanie J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ravindra Samadiya

Step 1

5 m)^4) / (64 * 200 GPa * (3 mm)^3 * (1 - 0.3^2)) Note: We need to convert the units to be consistent. 1 kPa = 1 N/m^2 and 1 GPa = 1,000,000 N/m^2. wmax = (10,000 N/m^2 * (1.5 m)^4) / (64 * 200,000,000,000 N/m^2 * (0.003 m)^3 * (1 - 0.3^2)) wmax = 0.000234375 m Show more…

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A simply-supported rectangular plate (at all edges) is considered under a uniformly distributed load P, as shown in the figure below. For the following data: P = 10 kPa, E = 200 GPa, v = 0.3, Lx = 1.5 m, Ly = 2.5 m, and thickness t = 3 mm. (a) Determine the maximum displacement (wmax) in the plate. (b) Obtain the maximum stress (Ïƒmax) inside the plate (Consider only 2 terms in x and y directions in your calculations.)