Question

54. A simply-supported steel beam is loaded by a distributed load as seen below. The elastic modulus of steel is 10,900 ksi and the moment of inertia about X-axis is 1500 in$^4$. The deflection at point C (2 ft from the left support) is most nearly: w = 3 lb/ft a) 0.1 in b) 0.2 in c) 0.3 in d) 0.4 in

          54. A simply-supported steel beam is loaded by a distributed load as seen below. The elastic modulus of steel is 10,900 ksi and the moment of inertia about X-axis is 1500 in$^4$. The deflection at point C (2 ft from the left support) is most nearly:
w = 3 lb/ft
a) 0.1 in
b) 0.2 in
c) 0.3 in
d) 0.4 in

54. A simply-supported steel beam is loaded by a distributed load as seen below. The elastic modulus of steel is 10,900 ksi and the moment of inertia about X-axis is 1500 in^4. The deflection at point C (2 ft from the left support) is most nearly:
w = 3 lb/ft
a) 0.1 in
b) 0.2 in
c) 0.3 in
d) 0.4 in

Added by John W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

05/23/2023

Step 1

The total load can be calculated by multiplying the distributed load (w) by the length of the beam (8 ft): Total load = w * length Total load = 3 lb/ft * 8 ft Total load = 24 lb Show more…

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A simply-supported steel beam is loaded by a distributed load as seen below. The elastic modulus of steel is 10,900 ksi and the moment of inertia about the X-axis is 1500 in^4. The deflection at point C (2 ft from the left support) is most nearly: a) 0.1 in b) 0.2 in c) 0.3 in d) 0.4 in 54. A simply-supported steel beam is loaded by a distributed load as seen below. The elastic modulus of steel is 10,900 ksi and the moment of inertia about the X-axis is 1500 in. The deflection at point C (2 ft from the left support) is most nearly: w = 3 lb/ft C 2 ft 8 ft a) 0.1 in b) 0.2 in c) 0.3 in d) 0.4 in