A single phase 100 kva 2400240 volt 60 hz distribution...

A single-phase 100-kVA, 2400/240-volt, 60-Hz distribution transformer is used as a step-down transformer. The load, which is connected to the 240-volt secondary winding, absorbs 80 kVA at 0.8 powerfactor lagging and is at 230 volts. Assuming an ideal transformer, calculate the following: (a) primaryvoltage, (b) load impedance, (c) load impedance referred to the primary, and (d) the real and reactivepower supplied to the primary winding

Transcript

00:01 This question we are given here 100 kilowatt transformer so we are given here transformer we can write here we are given here transformer of 2400 to 240 volt and 6 year distribution so we are given here 6 year frequency the distribution transformer used to step down transformer so we are given a step down transfer used as a step down transformer now in this question we are given here voltage so voltage v which is equal to we are given here is 230 volts we are given here 4 4 costs of questions so let's solve our first part of this question so in the first of part of this question we want to find the vp here we want to find bp means primary voltage we want to find primary voltage so we can write here we want to find here in the first part of this question we want to find primary voltage vp denoted by here vp now we know that in the transformer we know that primary voltage divided by secondary voltage which is equal to number of tons in a primary primary coil and divided by number of coils in a secondary number of tons in a secondary number of tons in a secondary so n is the number of tons now we just simplify this equation and we can write here vp which is equal to n1 divided by n2 multiplied by vs we just substitute value into this formula so we can write here 2400 divided by 240 multiplied by we can divide here 230 which is simply by this equation and we can write here the answer is 2300 volts so 20 ,300 the answer of our first subpart of this question now let's solve our second part of this question b so in the b or here we want to find load impedance so in the b we want to find load impedance so in the second subpart of this question we want to find here load impedance on the load impedance unit by z now we know that here as which is equal to here we are given here 80 kilowatt ampere and equal to we can write here v squared divided by z now before we just simplify this equation and we can write here z which is equal to v squared divided by s now we just substitute value into this formula so we can write here 230 square and s value is 80 so 80 multiplied by 10 to 3 now we just simplify this equation and we can write here the answer is so answer is 0 .661 20 125 ohum so this is the final answer of our second support of this question.

03:11 Now let's all about our third support of this question.

03:13 C...

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