A single slit has a width of 0.040 mm and is illuminated by 600 nm light. The diffraction pattern is observed on a screen 90 cm away from the slit. Determine the location of the first three dark fringes on one side of the central maximum.
Added by Ronald M.
Close
Step 1
040 \, mm = 0.040 \times 10^{-3} \, m = 4.0 \times 10^{-5} \, m$ Wavelength $\lambda = 600 \, nm = 600 \times 10^{-9} \, m = 6.0 \times 10^{-7} \, m$ Distance to screen $L = 90 \, cm = 0.9 \, m$ Show more…
Show all steps
Your feedback will help us improve your experience
Ravindra Yadav and 63 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Consider a single-slit diffraction pattem for $\lambda=589 \mathrm{nm},$ projected on a screen that is $1.00 \mathrm{m}$ from a slit of width $0.25 \mathrm{mm}$. How far from the center of the pattern are the centers of the first and second dark fringes?
Ravindra Y.
The width of the slit is 1.7 mm. Light with a wavelength of 420 nm passes through this slit and forms a diffraction pattern on a screen located 0.59 m away. In the diffraction pattern, find the width of the bright fringe, second dark fringe, first dark fringe, central bright fringe, and fifth dark fringe.
Adi S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD