a small 50 g block slides down a frictionless surface through height h = 20 cm and then sticks to a uniform rod of mass 100 g and length 40 cm. the rod pivots about point o through angle
Added by Myles M.
Step 1
First, we need to find the velocity of the block just before it hits the rod. We can use conservation of energy for this. The potential energy of the block at height h will be converted into kinetic energy when it reaches the bottom. Potential energy (PE) = m * g Show more…
Show all steps
Your feedback will help us improve your experience
Nicholas Mogoi and 74 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Fig. 11-58, a small $50 \mathrm{~g}$ block slides down a frictionless surface through height $h=20 \mathrm{~cm}$ and then sticks to a uniform rod of mass $100 \mathrm{~g}$ and length $40 \mathrm{~cm}$. The rod pivots about point $O$ through angle $\theta$ before momentarily stopping. Find $\theta$.
Conservation of Angular Momentum In Fig. $11-58,$ a small 50 $\mathrm{g}$ block slides down a frictionless surface through height $h=20 \mathrm{cm}$ and then sticks to a uniform rod of mass 100 g and length 40 $\mathrm{cm} .$ The rod pivots about point $O$ through angle $\theta$ before momentarily stopping. Find $\theta$
A rod OA rotates about a horizontal axis through $O$ with a constant anticlockwise velocity $\omega=3$ rad/sec. As it passes the position $\theta=0$ a small block of mass $m$ is placed on it at a radial distance $r=450 \mathrm{~mm}$. If the block is observed to slip at $\theta=50^{\circ}$, the coefficient of static friction between the block and the rod is: (Given that $\sin 50^{\circ}=0.766, \cos 50^{\circ}=0.64$ ) (a) $0.2$ (b) $0.55$ (c) $0.8$ (d) 1
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Watch the video solution with this free unlock.
EMAIL
PASSWORD