00:01
Hi, here in this given problem, first of all, this is a larger block which is moving towards right.
00:10
Suppose towards right with an acceleration a knot, where this a0 is given as 3 meter per second square.
00:18
Over it, there is a small block.
00:22
This is b.
00:23
This is a.
00:31
Mass of this block, m .a.
00:34
Let it be equal to m.
00:37
Now coefficient of friction between block a and b, this is given to be equal to 0 .2.
00:50
As the block b is moving towards right, so block a will experience a pseudo -force towards left.
01:01
So force of friction, kinetic friction will act between two blocks towards right.
01:07
If weight of the block a is mg, normal reaction will also be mg.
01:16
So force of friction will be given by mu k times m g.
01:22
So using free body diagram of the block a, that is f minus fk is equal to its mass multiplied by a.
01:43
F that is m into a not, should have force acting on it, minus fk that is mu k times mg is equal to m, canceling this m from both the sides...