00:01
Now we are going to understand this question.
00:05
Here, give it in the question, mass of block, mass of block that is represented by m, which is given 268 gram.
00:24
Or we can write 0 .268 kilogram because 1 gram is equal to, sorry, 1 kilogram is equal to 1000 gram.
00:36
So, 268 gram is equal to 0 .268 kilogram.
00:39
And vb is equal to 6 meter per second.
00:47
Let's see the diagram.
00:50
Vb is equal to 6 meter per second and distance between b and c that is represented by bbc, which is 10 meter.
01:03
Now in the part a, let the required work done by friction b, wf, the required work done, the required work done, by friction b, wf, now applying conservation of energy.
01:35
Now applying conservation of energy.
01:44
Conservation of energy.
01:50
So we can write mgh is equal to half mvb square plus work done by friction that is wf.
02:06
So we can write wf is equal to mgh minus half m bb square.
02:17
Now substituting the value in this, value of m that is 0 .268, value of g that is 9 .8 and value of h that is 4, minus 1 by 2 into value of m that is 0 .268 and value of b that is 6 .6 square.
02:37
So doing further calculation we will get 10 .5056 minus 4 .82 jules.
02:50
So after doing further calculation we will get wf is equal to 5 .682 jules.
03:02
Now solving part b...